-16x^2+45x+2.5=0

Solution for -16x^2+45x+2.5=0 equation:

-16x^2+45x+2.5=0

a = -16; b = 45; c = +2.5;
Δ = b2-4ac
Δ = 452-4·(-16)·2.5
Δ = 2185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{2185}}{2*-16}=\frac{-45-\sqrt{2185}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{2185}}{2*-16}=\frac{-45+\sqrt{2185}}{-32}
$